Practice question

X = (5×0)+(3×8)5+3 = 248 = 3. Y = (5×4)+(3×0)5+3 = 208 = 2.5. Distance = X2+Y2 = 32+(2.5)2 = 9+6.25 = 15.25≈3.9m. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 3.9 m. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.