Practice question

MCQ

Question

The solution of dydx = 1 - x^2 - y^2 + x^2y^2 is

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Choose one · Correct answer highlighted

sin-¹ y = sin-¹ x + c 2 ^ - 1y = 1 - x^2 + ^ - 1x + c 2 ^ - 1y = x 1 - x^2 + ^ - 1x + c Correct 2 ^ - 1y = x; 1 - x^2 + ^ - 1x + c

Explanation

Simply put, we verify 2 ^ - 1y = x 1 - x^2 + ^ - 1x + c by full calculation: use standard identity, substitute, simplify step by step to reach 2 ^ - 1y = x 1 -

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