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Question

The rms speed of a gas molecule is 400 m/s at 200 K. What is the rms speed at 800 K?

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Explanation

**Gas mixtures** ideal gas law applies to each component, P_total = Σ n_i R T/V, partial pressure P_i = n_i R T/V, mole tion X_i = n_i/n_total, P_i = X_i P_total, enabling calculation of individual pressures from composition, important for kinetic theory and chemistry. v_rms ∝ √(T), (v₂)/(v₁) = √((T₂)/(T₁)).(v₂)/(400) = √((800)/(200)) = √(4) = 2.v₂ = 400 × 2 = 800 m/s. Substituting values gives 800 m/s, which matches expected kinetic theory result, confirming mean free path λ = 1/(√2 n π d²), ideal gas law P V = n R T and v_rms = √(3 R T/M) relations.

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