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Question

The energy difference between the first and third orbits of a hydrogen atom is 1.936 × 10⁻¹⁸ J. What is the frequency of the photon emitted when an electron falls from n = 3 to n = 1? (h = 6.626 × 10⁻³⁴ J s)

Options

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Explanation

ν = ΔE/h ≈ 2.925×10¹⁵ Hz.

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