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Question

In the Carius method, a compound weighing 0.24 g produces 0.47 g of AgCl and 0.233 g of BaSO₄. What is the ratio of chlorine to sulphur by mass?

Options

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Explanation

Mass of Cl = (35.5/143.5) × 0.47 ≈ 0.116 g. Mass of S = (32/233) × 0.233 ≈ 0.032 g. Ratio = 0.116/0.032 ≈ 3.625:1, which rounds to 4:1 for practical purposes.