Practice question
Question
In a system where a charged conductor is placed inside a larger uncharged hollow conductor, why does
the inner conductor induce charges on both the inner and outer surfaces of the outer conductor?
Explanation
**System of charges** potential energy is sum over pairs U = Σ k q_i q_j/r_ij, work required to assemble charges from infinity. For 28 μC and -14 μC, 0.28 m apart, U=9×10⁹×28×(-14)×10⁻¹²/0.28= -12.6 J, negative indicates bound system. When a charged conductor (charge Q ) is placed inside a larger uncharged hollow conductor, the electric field from the inner charge induces -Q on the inner surface of the hollow conductor to ensure the field inside the conductor's material is zero. Since the hollow conductor is initially uncharged, its total charge must remain zero, so +Q appears on its outer surface to balance the induced -Q
Discussion
Comments
Please log in to join the discussion.
Login to commentNo comments yet. Be the first to start the discussion.