Skip to content

Question

In a double-slit experiment, if \( \lambda = 520 \, \text{nm} \), \( d = 0.4 \, \text{mm} \), and \( D
= 2.5 \, \text{m} \), what is the fringe width?

Options

Choose one · Correct answer highlighted

Explanation

**Coherence** requires constant phase difference, two independent sources not coherent because phase random, prevents interference pattern, laser coherent, visibility of fringes determined by coherence, intensity and phase difference, coherent sources produce stable interference, incoherent intensity adds I = I₁+I₂ no interference, interference pattern distinguishes from diffraction. Fringe width β = (λ D/d) . λ = 5.2 × 10⁻⁷ m , d = 4.0 × 10⁻⁴ m , D = 2.5 m . β = (5.2 × 10⁻⁷ × 2.5/4.0 × 10⁻⁴) = 3.25 × 10⁻³ m = 3.25 mm . Using Δ = d sinθ, y = n λ D/d, a sinθ = n λ,

Discussion

Comments

0 comments

No comments yet. Be the first to start the discussion.