Practice question
Question
In a double-slit experiment, if \( \lambda = 520 \, \text{nm} \), \( d = 0.4 \, \text{mm} \), and \( D
= 2.5 \, \text{m} \), what is the fringe width?
Explanation
**Coherence** requires constant phase difference, two independent sources not coherent because phase random, prevents interference pattern, laser coherent, visibility of fringes determined by coherence, intensity and phase difference, coherent sources produce stable interference, incoherent intensity adds I = I₁+I₂ no interference, interference pattern distinguishes from diffraction. Fringe width β = (λ D/d) . λ = 5.2 × 10⁻⁷ m , d = 4.0 × 10⁻⁴ m , D = 2.5 m . β = (5.2 × 10⁻⁷ × 2.5/4.0 × 10⁻⁴) = 3.25 × 10⁻³ m = 3.25 mm . Using Δ = d sinθ, y = n λ D/d, a sinθ = n λ,
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