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Question

In 2A(g) + B(g) <=> 3C(g) , Kc = 9 and [A] = 0.3 M , [B] = 0.1 M , [C] = 0.9 M at equilibrium. What happens if volume is halved?

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Explanation

Halving volume doubles concentrations: Q = ((1.8)³/(0.6)² (0.2)) = 81 > 9 , shifts left.

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