Skip to content

Question

How much work is done by 1 mole of an ideal gas in an isothermal expansion from 3 L to 9 L at 500 K ? ( R = 8.3 J mol⁻¹ K⁻¹ )

Options

Choose one · Correct answer highlighted

Explanation

**Adiabatic work** W = ∫ P dV = (P₁V₁ - P₂V₂)/(γ-1), for expansion V₂>V₁ P₂

Discussion

Comments

0 comments

No comments yet. Be the first to start the discussion.