Practice question
Question
How much heat is required to raise the temperature of 0.5 moles of neon by 25 K at constant volume? (R = 8.31 J mol^{-1 K^{-1)
Explanation
Given:
How much heat is required to raise the temperature of 0.5 moles of neon by 25 K at constant volume? (R = 8.31 J mol^{-1 K^{-1)
These values define the system as per NCERT data.
Formula:
For monatomic gas, C_v = 3/2 R.
This is the standard NCERT relation for this phenomenon.
Substitution & Calculation:
Q = μ C_v Δ T = 0.5 × 3/2 × 8.31 × 25 = 155.8125 J approx 155.8 J.
Result:
The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
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