Practice question
Question
How much heat is required to raise the temperature of 0.15 kg of copper from 40^circ C to 60^circ C ? (Specific heat of copper = 386.4 J kg⁻¹ K⁻¹ )
Explanation
**Heat engine** absorbs Q_h from hot reservoir T_h, does work W, rejects Q_c to cold T_c, efficiency η = W/Q_h =1 - Q_c/Q_h, second law limits η <1, Kelvin-Planck forbids perfect engine with Q_c=0, Clausius statement heat cannot flow spontaneously from cold to hot without work, equivalent to Kelvin-Planck. Δ Q = m s Δ T . m = 0.15 , s = 386.4 , Δ T = 60 - 40 = 20 . Δ Q = 0.15 × 386.4 × 20 = 1159.2 J ≈ 1159 J . Using first law ΔU = Q - W, W = ∫ P dV, isobaric W =
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