Practice question
Question
How much heat is required to raise 0.8kg of aluminium from 25∘C to 75∘C if its specific heat capacity is 900J kg−1K−1?
Explanation
Given: m = 0.8kg, ΔT = 75−25 = 50∘C, s = 900Jkg−1K−1. Q = msΔT = 0.8×900×50 = 36000J = 36kJ. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 36 kJ. This satisfies dimensional consistency and physical conditions given, so option A is scientifically correct.
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