Practice question
Question
How much heat is needed to convert 0.2kg of water at 100∘C to steam at 100∘C? (Latent heat of vaporization = 2.256×106J kg−1)
Explanation
Given: m = 0.2kg, Lv = 2.256×106J kg−1. Q = mLv = 0.2×2.256×106 = 451200J = 451.2kJ. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 451.2 kJ. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
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