Practice question
Question
For 2SO₃(g) <=> 2SO₂(g) + O₂(g) , Kc = 0.02 at 700 K. If 0.4 mol SO₃ is in a 2 L vessel, what is [O₂] at equilibrium?
Explanation
Initial: [SO₃] = 0.2 M , [SO₂] = [O₂] = 0 . Let x = [O₂] , [SO₂] = 2x , [SO₃] = 0.2 - 2x . Kc = ([SO₂]²[O₂]/[SO₃]²) = ((2x)² x/(0.2 - 2x)²) = 0.02 , 4x³ = 0.02 (0.04 - 0.8x + 4x²) , x ≈ 0.016 M .
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