Practice question
Question
For 2A(g) + B(g) <=> 3C(g) , Kp = 2 at 700 K. If PA = 1 atm , PB = 0.5 atm initially, what is PC at equilibrium?
Explanation
Let PC = 3x , PA = 1 - 2x , PB = 0.5 - x . Kp = ((PC)³/(PA)² PB) = ((3x)³/(1 - 2x)² (0.5 - x)) = 2 , 27x³ = 2 (1 - 2x)² (0.5 - x) , x ≈ 0.2 , PC = 0.6 atm .
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