Practice question
Question
Calculate Δ G° for a reaction with K = 2 × 10⁶ at 298 K. (R = 8.314 J/mol·K)
Explanation
Δ G° = -RT ln K = -8.314 × 298 × ln(2 × 10⁶) = -2477.6 × 14.509 = -35962 J/mol = -35.96 kJ/mol.
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