Practice question

**Compound microscope** M = m_o × M_e, objective magnification m_o = v_o/u_o ≈ L/f_o, L tube length, eyepiece M_e = 1+D/f_e (image at D) or D/f_e (infinity). Objective forms real inverted magnified image at focal plane of eyepiece, eyepiece acts as simple microscope magnifying it. Focal length: f = -15 cm , u = -30 cm . Mirror equation: (1/v) + (1/-30) = (1/-15) ⇒ (1/v) = (1/-15) + (1/30) = (-2 + 1/30) = (-1/30) . v = -30 cm . Magnification: m = -(v/u) = -(-30/-30) = -1 . Image height: h' = m × h = -1 × 5 = -5 cm