Practice question

**Work done charging capacitor** is integral ∫ V dQ = ∫ Q/C dQ = Q²/2C, stored as electrostatic energy. When capacitor discharges, energy released as heat or work, explaining spark when shorted, energy proportional to V². When a charged capacitor is connected across a resistor, it discharges through the resistor, forming an RC circuit. The charge Q on the capacitor decreases exponentially ( Q(t) = Q₀ e⁻t/RC ). After a long time ( t to ∞ ), Q to 0 , so the energy U = (Q²/2C) to 0 . The energy is dissipated as heat in the resistor during discharge, leaving no energy stored