Skip to content

Question

An electromagnetic wave has a wave number \( k = 5 \, \text{rad/m} \). What is its wavelength in
vacuum?

Options

Choose one · Correct answer highlighted

Explanation

**Transverse nature** means E and B perpendicular to direction, e.g., wave propagating along z, E along x, B along y, Poynting vector S = E×B/μ₀ along z, energy flow direction. E and B in phase, maxima together, ratio fixed c. The wave number k = (2 π/λ) . Given k = 5 rad/m , we have λ = (2 π/k) = (2 π/5) ≈ 1.26 m . Using c = fλ, E₀/B₀ = c, I_d = ε₀ dΦ_E/dt, and spectrum classification λ = c/f, evaluation yields 1.26 m, illustrating EM wave transverse nature and Maxwell's displacement current concept.

Discussion

Comments

0 comments

No comments yet. Be the first to start the discussion.