Practice question
Question
A thin ring of mass 3kg and radius 0.5m rotates at 8rad/s. What is its angular momentum about its axis?
Explanation
I = MR2 = 3×(0.5)2 = 0.75kg m2. L = Iω = 0.75×8 = 6kg m2/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 6.0 kg m²/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
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