Practice question
Question
A system in a cyclic process absorbs 650 J of heat and performs 200 J of work. What is the heat rejected?
Explanation
**Latent heat** energy needed for phase change without temperature change, overcomes intermolecular forces, e.g., heating ice at 0°C to water at 0°C requires 334 kJ/kg, then heating water to 100°C requires c ΔT, then vaporization 2260 kJ/kg, illustrating two types of heat. For cyclic: Δ U = 0 , Q_net = W . Q_absorb - Q_reject = W . 650 - Q_reject = 200 ⇒ Q_reject = 650 - 200 = 450 J . Using first law ΔU = Q - W, W = ∫ P dV, isobaric W = P ΔV, isothermal W = n R T ln(V₂/V₁), adiabatic P V^γ = const and
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