Practice question
Question
A steel wire of length 4 m and cross-sectional area 2 × 10-6 m2 is stretched by 0.4 mm. If the force applied is 200 N, what is the Young's modulus of the steel?
Explanation
Young's modulus: Y = (F L) / (A ΔL). Substitute: ΔL = 0.4 × 10-3 m. Y = (200 × 4) / (2 × 10-6 × 0.4 × 10-3) = 800 / (8 × 10-10) = 1 × 1012 N/m2.
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