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Practice question

MCQ

Question

A steel rod of length 1 m and diameter 2 mm is subjected to a tensile force producing a stress of 5 × 107 N/m2. What is the force applied? (Take π ≈ 3.14)

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Explanation

Stress: Stress = F / A. Area: A = π r2, r = 1 × 10-3 m. A = 3.14 × (1 × 10-3)2 = 3.14 × 10-6 m2. Force: F = Stress × A = 5 × 107 × 3.14 × 10-6 = 157 N.

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