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Question

A simple microscope with a lens of focal length \( 10 \, \text{cm} \) forms an image at the least
distance of distinct vision (\( 25 \, \text{cm} \)). What is the magnification?

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Explanation

**Combination of lenses in contact** effective power P = P₁+P₂, effective focal length 1/F = 1/f₁ + 1/f₂, for thin lenses in contact. If separated by d, 1/F =1/f₁+1/f₂ - d/(f₁ f₂). Power adds algebraically, converging + with diverging - can cancel, used to correct aberrations and design achromatic doublets. Magnification: m = 1 + (D/f) . D = 25 cm , f = 10 cm . m = 1 + (25/10) = 1 + 2.5 = 3.5 . Substituting values gives 3.5, which matches expected image position and magnification from mirror/lens formula 1/f = 1/v - 1/u (lens) or 1/f = 1/v + 1/u

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