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Question

A simple microscope with a focal length of \( 10 \, \text{cm} \) forms an image at \( 25 \, \text{cm}
\). What is the magnification?

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Explanation

**Compound microscope** M = m_o × M_e, objective magnification m_o = v_o/u_o ≈ L/f_o, L tube length, eyepiece M_e = 1+D/f_e (image at D) or D/f_e (infinity). Objective forms real inverted magnified image at focal plane of eyepiece, eyepiece acts as simple microscope magnifying it. Magnification: m = 1 + (D/f) . D = 25 cm , f = 10 cm . m = 1 + (25/10) = 1 + 2.5 = 3.5 . Substituting values gives 3.5, which matches expected image position and magnification from mirror/lens formula 1/f = 1/v - 1/u (lens) or 1/f = 1/v + 1/u (mirror), confirming sign conventions and refraction principles.

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