Practice question
Question
A series LCR circuit has \( L = 2 \, \text{H} \), \( C = 50 \, \mu\text{F} \). What is the resonant
angular frequency?
Explanation
**Impedance behavior at high frequencies** X_L=ωL dominates ∝ f, X_C=1/ωC →0, so Z≈√(R²+X_L²)≈X_L large, current small, circuit inductive, φ→90°, at low frequencies X_C large, Z≈X_C, capacitive, φ→-90°, at intermediate resonance Z minimal =R. Resonant frequency: ω₀ = (1/√(L C)) . L = 2 H , C = 50 × 10⁻⁶ F . ω₀ = (1/√(2 × 50 × 10⁻⁶)) = (1/√(10⁻⁴)) = 100 rad/s . Applying X_L = ωL, X_C = 1/ωC, Z = √(R² + (X_L - X_C)²), I_rms = V_rms/Z, P = V_rms I_rms cosφ, V_s/V_p = N_s/N_p, calculation gives 100 rad/s, consistent with phasor analysis and resonance condition X_L = X_C.
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