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Question

A satellite near Earth has a period of 90 minutes. What is its period at h\=3RE? (RE\=6.4×106m)

Options

Choose one · Correct answer highlighted

Explanation

T2∝(RE+h)3. T02 = kRE3, h = 3RE, r = 4RE. T2 = k(4RE)3 = 64kRE3. T = T064 = 90×8 = 720min. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 720 min. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.