Practice question
Question
A reaction has Δ H = -200 kJ/mol and Δ S = -250 J/K. At what temperature does it cease to be spontaneous?
Explanation
Δ G = 0 at equilibrium, Δ H - TΔ S = 0, -200 × 10³ - T(-250) = 0, T = 200000 / 250 = 800 K. Spontaneous below 800 K.
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