Practice question
Question
A long wire carries \( 20 \, \text{A} \). At what distance from the wire is the magnetic field \( 4
\times 10^{-6} \, \text{T} \)? (\( \mu_0 = 4 \pi \times 10^{-7} \, \text{T m/A} \))
Explanation
**Effect of doubling velocity** on magnetic force F = q v B sinθ is linear increase, F doubles for same θ and B. Electron with charge 1.6×10⁻¹⁹ C, v = 4.5×10⁶ m/s, B = 0.35 T, θ = 90°, F = 1.6×10⁻¹⁹×4.5×10⁶×0.35 = 2.52×10⁻¹³ N, illustrating magnitude for typical lab values. B = (μ₀ I/2 π r) , so r = (μ₀ I/2 π B) . r = (4 π × 10⁻⁷ × 20/2 π × 4 × 10⁻⁶) = (8 × 10⁻⁶/8 × 10⁻⁶) = 1 m . Using F = q v B sinθ, F = I l B sinθ, B = μ₀
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