Practice question
Question
A long straight wire carries a current of \( 40 \, \text{A} \). What is the magnetic field at a
distance of \( 0.5 \, \text{m} \) from it? (\( \mu_0 = 4 \pi \times 10^{-7} \, \text{T m/A} \))
Explanation
**SI unit of magnetic field** is tesla (T), defined as force 1 N on 1 A·m wire perpendicular to field. Moving coil galvanometer uses torque τ = N I A B balanced by spring torque k φ, so deflection φ ∝ I, enabling current measurement, with radial field ensuring τ = N I A B always maximum. Magnetic field B = (μ₀ I/2 π r) . B = (4 π × 10⁻⁷ × 40/2 π × 0.5) = (160 × 10⁻⁷/1) = 1.6 × 10⁻⁵ T . Using F = q v B sinθ, F = I l B sinθ, B = μ₀ I/(2π r),
Discussion
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