Practice question
Question
A hydraulic lift raises a 1400kg load using a small piston of radius 2.5cm and a large piston of radius 10cm. What force is applied on the small piston? (Take g\=9.8m/s2)
Explanation
F1 = A1A2F2, F2 = 1400×9.8 = 13720N. A1 = π(0.025)2, A2 = π(0.1)2, A1A2 = 0.0006250.01 = 116. F1 = 1372016 = 857.5N≈858N. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 858 N. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
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