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Question

A hydraulic lift has a small piston of area 0.01m2 and a large piston of area 0.09m2. If a force of 100N is applied on the small piston, what is the force exerted by the large piston?

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Explanation

By Pascal’s law, pressure is transmitted equally: P = F1A1 = F2A2. F2 = F1×A2A1. F1 = 100N, A1 = 0.01m2, A2 = 0.09m2. F2 = 100×0.090.01 = 100×9 = 900N.

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