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Question

A gas undergoes an adiabatic expansion from 10 L to 40 L , reducing its pressure from 8 atm to 1 atm . What is the value of gamma ?

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Explanation

**Heat capacity** at constant pressure C_p and volume C_v, C_p = C_v + R per mole, for solids Dulong-Petit C_v≈3R≈25 J/mol·K. Specific heat and latent heat govern temperature changes and phase transitions, Q = m c ΔT for heating, Q = m L for melting/boiling at constant T. For adiabatic: P₁ V₁^γ = P₂ V₂^γ . 8 × 10^γ = 1 × 40^γ . 8 = ((40)/(10))^γ ⇒ 8 = 4^γ . 4^γ = 2³ ⇒ 2²γ = 2³ ⇒ 2γ = 3 ⇒ γ = 1.5 . Using first law ΔU = Q - W, W = ∫ P dV, isobaric W = P

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