Practice question
Question
A gas has a Henry’s law constant of 500 bar at 25°C. If the partial pressure increases from 5 bar to 10 bar, what is the percentage increase in solubility?
Explanation
Initial x = (5/500) = 0.01 . New x = (10/500) = 0.02 . Percentage increase = (0.02 - 0.01/0.01) × 100 = 100% .
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