Practice question
Question
A gas follows Henry’s law with a constant of 200 bar. If its solubility in a solvent is 0.015 mol/kg at 3 bar, what is the mass of solvent required to dissolve 0.03 mole of the gas at the same pressure?
Explanation
Molality = (moles/mass of solvent in kg) . 0.015 = (n/m) , at p = 3 bar , x = (3/200) = 0.015 (molality ≈ x for dilute solutions). For 0.03 mole: 0.015 = (0.03/m) , m = (0.03/0.015) = 2 kg = 2000 g .
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