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Question

A gas expands from 4L to 6L at constant pressure of 2atm and temperature 300K. What is the new temperature if the volume is reduced back to 4L at constant pressure?

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Explanation

At constant pressure, V1T1 = V2T2. Initial: V1 = 4L, T1 = 300K, V2 = 6L, T2 = ?. T2 = T1×V2V1 = 300×64 = 450K. Back to 4L: T3 = T2×V3V2 = 450×46 = 300K (original temperature).