Practice question
Question
A gas expands from 4L to 6L at constant pressure of 2atm and temperature 300K. What is the new temperature if the volume is reduced back to 4L at constant pressure?
Explanation
At constant pressure, V1T1 = V2T2. Initial: V1 = 4L, T1 = 300K, V2 = 6L, T2 = ?. T2 = T1×V2V1 = 300×64 = 450K. Back to 4L: T3 = T2×V3V2 = 450×46 = 300K (original temperature).