Practice question
Question
A gas at 2.8atm and 97∘C occupies 3.8L. If the temperature is raised to 147∘C and volume reduced to 2.5L, what is the final pressure?
Explanation
Given: P1 = 2.8atm, T1 = 97∘C = 370K, V1 = 3.8L, T2 = 147∘C = 420K, V2 = 2.5L. P1V1T1 = P2V2T2. P2 = P1×V1V2×T2T1 = 2.8×3.82.5×420370. P2 = 2.8×1.52×1.1351≈4.83atm.