Practice question
Question
A gas at 27∘C and 2atm occupies 4L. If the temperature is increased to 127∘C and pressure is reduced to 1atm, what is the new volume?
Explanation
Given: T1 = 27∘C = 300K, P1 = 2atm, V1 = 4L, T2 = 127∘C = 400K, P2 = 1atm. Ideal gas law: P1V1T1 = P2V2T2. V2 = V1×P1P2×T2T1 = 4×21×400300 = 4×2×43 = 10.67L.