Practice question
Question
A gas at 1atm and 300K occupies 2L. If it is compressed to 0.5L while temperature rises to 450K, what is the final pressure?
Explanation
Given: P1 = 1atm, V1 = 2L, T1 = 300K, V2 = 0.5L, T2 = 450K. P1V1T1 = P2V2T2. P2 = P1×V1V2×T2T1 = 1×20.5×450300 = 1×4×1.5 = 6atm. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 6 atm. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.