Practice question
Question
A force F\=−2i^+3j^N acts at r\=1i^+2j^m. What is the torque about the origin?
Explanation
τ = r×F = |i^j^k^120−230| = k^(1×3−2×(−2)) = k^(3+4) = 7k^Nm. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 7 Nm. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.