Practice question

**Effect of dielectric** is to reduce effective field due to polarization, bound surface charges opposite to free charges, net field E = E₀ - E_p = E₀/K. Capacitance C = Q/V = K ε₀ A/d for full filling, partial filling C = ε₀ A/(d - t + t/K) for slab thickness t. When a dielectric slab (with dielectric constant K > 1 ) is inserted between the plates of a capacitor with constant voltage V , the electric field E in the dielectric region decreases. The electric field in a dielectric is given by E = (E₀/K) , where E₀ = (V/d) is the field