Skip to content

Question

A copper wire of length 2.5m and cross-sectional area 2×10−6m2 is stretched by a force of 200N. If the Young's modulus of copper is 1.1×1011N/m2, what is the stress?

Options

Choose one · Correct answer highlighted

Explanation

Stress: Stress = FA = 2002×10−6 = 1×108N/m2. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1×108N/m2. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Discussion

Comments

0 comments

No comments yet. Be the first to start the discussion.