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Question

A copper rod of density 8960 kg/m³ has a speed of sound of 3600 m/s. What is its Young’s modulus?

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Explanation

**Sinusoidal wave form** represents harmonic wave where each particle executes SHM. Coefficients of x and t give spatial and temporal periodicities, allowing wavelength and period extraction, basis for wave analysis in NCERT. Speed: v = √((Y/rho)) . 3600 = √((Y/8960)) ⇒ 3600² = (Y/8960) . Y = 3600² × 8960 = 1.16 × 10¹¹ Pa . Using v = fλ and standing-wave condition fₙ = n v/(2L) or v/(4L) as applicable, calculation yields 1.16 × 10¹¹ Pa, illustrating frequency-length-speed interdependence and quantization by boundaries.

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