Practice question

Given: A conductor has a surface charge density of 1.5 × 10⁻⁶C/m² . What is the electric field just outside it? (Take ε_0 = 8.85 × 10⁻¹²C² N^{-1 m^{-2 ). Formula: E = sigma/ε_0 = frac1.5 × 10⁻⁶⁸.85 × 10⁻¹²approx 1.695 × 10⁵N/C .. Substitution: Substituting given values into formula as per NCERT 2026-27 method. Calculation: Simplifying step by step with proper SI units like m/s², J kg⁻¹ K⁻¹, 10⁻⁵, A m⁻¹ etc. Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.