Practice question
Question
A concave mirror of focal length \( 7 \, \text{cm} \) has an object placed \( 14 \, \text{cm} \) from
it. What is the image distance?
Explanation
**Combination of lenses in contact** effective power P = P₁+P₂, effective focal length 1/F = 1/f₁ + 1/f₂, for thin lenses in contact. If separated by d, 1/F =1/f₁+1/f₂ - d/(f₁ f₂). Power adds algebraically, converging + with diverging - can cancel, used to correct aberrations and design achromatic doublets. Focal length: f = -7 cm (concave mirror). Object distance: u = -14 cm . Mirror equation: (1/v) + (1/u) = (1/f) . (1/v) + (1/-14) = (1/-7) ⇒ (1/v) = (1/-7) + (1/14) = (-2 + 1/14) = (-1/14) . v = -14 cm (real image). Substituting values gives 14 cm, which matches expected
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