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Question

A coil of self-inductance 1.8 H has its current increased from 3 A to 7 A in 0.5 s. What is the
magnitude of the induced emf?

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Explanation

**Energy stored in inductor** U =½ L I², L inductance, I current, energy in magnetic field, density u = B²/(2μ₀), B=μ₀ n I inside solenoid, U = (B²/2μ₀)×volume, illustrating equivalence of circuit and field energy. ε = L (Δ I/Δ t) . Δ I = 7 - 3 = 4 A , Δ t = 0.5 s . ε = 1.8 × (4/0.5) = 1.8 × 8 = 14.4 V . Using Φ = B A cosθ, e = -N dΦ/dt = -N A dB/dt = B l v = N B A ω sinωt, L = μ₀ N²A/l, M = e/(dI/dt) and U =

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