Practice question
Question
A charge of \( 5 \, \mu\text{C} \) is moved from infinity to a point where the potential is \( 300 \,
\text{V} \). What is the work done?
Explanation
**Relation E = -∇V** shows field points down potential gradient. For system of opposite charges close together, equipotential near midpoint between them has V≈0, but shape distorted, not spherical, reflecting superposition of potentials V = k q₁/r₁ + k q₂/r₂. Work done = Potential energy = q V . W = 5 × 10⁻⁶ × 300 = 1.5 × 10⁻³ J = 1.5 mJ . Using V = kQ/r, U = k q₁q₂/r, E = -dV/dr, C = ε₀A/d, 1/C_eq series, C_eq = ΣC parallel, U = ½ C V² and common potential V = Q_total/C_total, result 1.5 mJ follows, reflecting potential-capacitance relations.
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