Practice question
Question
A brass rod of length 2 m and cross-sectional area 5 × 10-6 m2 is compressed by a force of 1000 N. If the Young's modulus of brass is 9 × 1010 N/m2, what is the longitudinal strain?
Explanation
Stress: Stress = F / A = 1000 / (5 × 10-6) = 2 × 108 N/m2. Young's modulus: Y = Stress / Strain. Strain: Strain = Stress / Y = (2 × 108) / (9 × 1010) ≈ 2.22 × 10-3.