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Practice question

MCQ

Question

A brass block of dimensions 0.3 m × 0.2 m × 0.1 m is subjected to a shearing force of 5 × 104 N. If the shear modulus of brass is 3.6 × 1010 N/m2, what is the displacement of the upper face?

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Explanation

Shear modulus: G = (F / A) / (Δx / L). Rearrange: Δx = (F L) / (A G). Area: A = 0.3 × 0.2 = 0.06 m2, L = 0.1 m. Substitute: Δx = (5 × 104 × 0.1) / (0.06 × 3.6 × 1010) = 5000 / (2.16 × 109) ≈ 2.31 × 10-6 m.

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