Practice question
Question
A 300 mL solution contains 11.7 g of NaCl and has a density of 1.01 g/mL. What is its molarity? (Molar mass: NaCl = 58.5 g/mol)
Explanation
Moles of NaCl = 11.7/58.5 = 0.2 mol. Volume = 300 mL = 0.3 L. Molarity = 0.2/0.3 ≈ 0.667 M.
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